![]() Than one outcome that's associated with this. Possible outcomes are associated with this event? You could call this Possible outcomes, or the size of our sample Our sample space? I have eight possible outcomes. Probability of exactly two heads, I'll say H'sĮxactly two heads, well what is the size of ![]() Say that this is the first flip, the secondįlip, and the third flip. The different ways that I could flip three coins. Tails, heads, or I could get heads, tails, tails. Head, flip two I get a head, flip three I get a head. ![]() Of getting exactly two heads when flipping three coins. Either way, the answer is 190 possible ways to throw exactly 2 heads. Or you can add it all up on a calculator. Now I happen to know a neat little trick to work out 19+18+17+.+2+1, just ask if you want to know it. + 2 + 1 = number of ways to throw exactly 2 heads in 20 throws. This logic gives you 19 ways + 18 + 17 +. Right down to the first head falling on the 19th throw, when the 20th throw must also be a head, so only one way there. If the first head falls on the 3rd throw, there are 17 ways to get exactly 2 heads. Then I think of the ways I could throw exactly 2 heads if my first head was on the 2nd throw - there would be 18 throws left and my second head could fall in any one of those, so 18 ways to throw exactly 2 heads with the first head on the 2nd throw. First I think of if I threw a head the very first throw - there would be the 19 other possible throws in which I could throw the second head, so 19 ways to throw a head first throw plus just one other head in that session. Total outcomes with exactly 2 heads - I imagine all the ways that I could definitely throw exactly 2 heads. That's 2 possible outcomes per throw, times itself 20 times because it happens 20 times over
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